Topic: opening all fonts from a folder • RoboFont

This topic contains 6 replies, has 2 voices, and was last updated by frederik 5 years, 10 months ago.

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December 10, 2014 at 10:39 #6051
luke
Member
hi frederik,
is there an easy way to open all fonts from a folder.
when using this, I would have to open one after another.
```
f = OpenFont("/path/file.ufo", showUI=False)
```
maybe you could help me with this, thank you very much!
December 10, 2014 at 10:48 #6052
frederik
Keymaster
you can use something like this
```
from lib.tools.misc import walkDirectoryForFile

root = "/my/Fonts/Folder"
for path in walkDirectoryForFile(root, ".ufo"):
    OpenFont(path)
```
December 10, 2014 at 11:27 #6055
luke
Member
thank you very much!
```
OpenFont(path, showUI=False)
```
instead of
```
OpenFont(path)
```
does not seem to work in this case?
or should that also work?
December 10, 2014 at 11:33 #6056
luke
Member
sorry, or maybe it works – lets put it then in other words:
how is it possible to access/see what is open (without an UI).
```
print AllFonts()
```
does’nt work in this case.
December 12, 2014 at 07:32 #6059

luke
Member

Okay, got it. Thanks a lot!

December 13, 2014 at 21:35 #6060

frederik
Keymaster

well AllFonts() just return all fonts with an UI. If you open a font without a UI (with showUI=False) your script knows which fonts you opened. You can store them in a list if you like.

good luck

December 20, 2014 at 15:59 #6064

frederik
Keymaster

Thank you Frederik,
already found a solution – one thing: should observers like “FontDidOpen” or “FontWillOpen” work with OpenFont(path, showUI=False).
Thanks in Advance.

Hi Luke
I’ve split your unrelated question into a different topic see http://doc.robofont.com/forums/topic/split-opening-italic-otfs/

when you open a font without a UI, your script knows when and where it did/will open, so you don’t need those notifications…
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